2(9x^2)=9

Solution for 2(9x^2)=9 equation:

2(9x^2)=9

We move all terms to the left:

2(9x^2)-(9)=0

a = 29; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·29·(-9)
Δ = 1044
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1044}=\sqrt{36*29}=\sqrt{36}*\sqrt{29}=6\sqrt{29}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{29}}{2*29}=\frac{0-6\sqrt{29}}{58}
=-\frac{6\sqrt{29}}{58}
=-\frac{3\sqrt{29}}{29}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{29}}{2*29}=\frac{0+6\sqrt{29}}{58}
=\frac{6\sqrt{29}}{58}
=\frac{3\sqrt{29}}{29}
$